tmval.amt_from_intdisc

growth.amt_from_intdisc(dex: Tuple[float, float], x0: Union[float, numpy.ndarray] = array([0.001, 0.01109091, 0.02118182, 0.03127273, 0.04136364, 0.05145455, 0.06154545, 0.07163636, 0.08172727, 0.09181818, 0.10190909, 0.112, 0.12209091, 0.13218182, 0.14227273, 0.15236364, 0.16245455, 0.17254545, 0.18263636, 0.19272727, 0.20281818, 0.21290909, 0.223, 0.23309091, 0.24318182, 0.25327273, 0.26336364, 0.27345455, 0.28354545, 0.29363636, 0.30372727, 0.31381818, 0.32390909, 0.334, 0.34409091, 0.35418182, 0.36427273, 0.37436364, 0.38445455, 0.39454545, 0.40463636, 0.41472727, 0.42481818, 0.43490909, 0.445, 0.45509091, 0.46518182, 0.47527273, 0.48536364, 0.49545455, 0.50554545, 0.51563636, 0.52572727, 0.53581818, 0.54590909, 0.556, 0.56609091, 0.57618182, 0.58627273, 0.59636364, 0.60645455, 0.61654545, 0.62663636, 0.63672727, 0.64681818, 0.65690909, 0.667, 0.67709091, 0.68718182, 0.69727273, 0.70736364, 0.71745455, 0.72754545, 0.73763636, 0.74772727, 0.75781818, 0.76790909, 0.778, 0.78809091, 0.79818182, 0.80827273, 0.81836364, 0.82845455, 0.83854545, 0.84863636, 0.85872727, 0.86881818, 0.87890909, 0.889, 0.89909091, 0.90918182, 0.91927273, 0.92936364, 0.93945455, 0.94954545, 0.95963636, 0.96972727, 0.97981818, 0.98990909, 1.0]), precision: int = 5) → tmval.growth.Amount[source]

Given interest earned over a time period on an unknown investment amount, and discount earned over a time period, on that same amount, generates an Amount object.

For example, if you can earn 500 in interest in two years, and the discount in one year is 200, you can supply iex=[400, 2], dex=[200,1]

Parameters

  • iex (Tuple[float, float]) – The interest earned over a time interval.

  • dex (Tuple[float, float]) – The discount earned over a time interval.

  • x0 – A starting guess or list of guesses for Newton’s method, defaults to np.linspace(.001, 1, 100).

  • precision (int) – rounding precision used to remove duplicates from Newton’s method, defaults to 5.

Returns

An amount function.

Return type

Amount